A circle having radius 5 units and passing through point (4,3) and its centre lies on line 2x+y-1=0.. Find the equation of circle Answer: (x - 1)² + (y + 1)² = 5² or (x + 1)² + (y - 3)² = 5² Step-by-step explanation: We know that the equation of a circle is expressed as (x - h)² + (y - k)² = r² Given: r = 5 Unknown: (h, k) To solve for the center, were given the following clues; (1) the circle is passing through point (4, 3) (2) the center lies on the line 2x + y - 1 = 0 Identify the two equations in which you can get the center of the circle; Equation 1 = 2x + y - 1 = 0 Equation 2 = *I used the distance formula in equation 2. This will help me identify the missing center of the circle. Solve for y in equation 1: 2x + y - 1 = 0 2x + y = 1 y = 1 - 2x Substitute the value of y in equation 2: Substitute the value of x in equation 1: When x = 1, y = -1 When x = -1, y = 3 Substitute the values of x and y to (h, k). Yoll then get: (x - 1)² + (y + 1)² = 5² or (x + 1)² + (y - 3)² = 5² ^...
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x²+y²+4x-4y-28=0 to standard form then give the coordinates of the center and the radius ( i hope yall help me) Answer: The coordinates of the center of the circle is (-2,2) while its radius is 6. Step-by-step explanation: Step 1: Write the given The equation is an equation for circle since the coefficient and sign of and is equal. Step 2: Find the center-radius form of the given as well as the center coordinates and the radius of the circle. Center-radius form: Where (h,k) will be the coordinates of the center of the circle In order to transform the given equation into the center-radius form then we will use the technique "completing the square" Group the terms with the same variable and isolate the constant: In completing the square, we need to work both on x and y variable separately. Divide the coefficient of 4x by 2 and square the resulting answer: Divide teh coefficient of -4y by 2 and square the resulting answer: The equation will result to: 4+4 is also added ...
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